九九乘法口诀表
小学六年级语文试卷-深圳旅游景点
relationship, established equivalent
relationship 14, and subject: application problem
(4)--scores and percentage application problem
review content overview answers scores, and
percentage application problem of key is:
according to meanings hen in-line solution.
Category fraction multiplication word problem
score Division applications engineering problem
problem XV, a subject: review of the measurement
of the amount of capacity, measurement and units
of measurement of common units of measurement and
their significance in rate 1, currency, length,
area, volume, unit size, volume, w
and subject:
geometry preliminary knowledge (1)--line and angle
review content line, and segment, and Ray, and
vertical, and parallel, and angle angle of
classification (slightly) 17, and subject:
geometry preliminary knowledge (2)--plane
graphi
, (1) determine standard vol
cs
review content triangle, a
ume (unit
nd
edges shaped, and round, and fan axisymmetric
graphics perimeter and area combination graphics
of area subject : Preliminary knowledge (3)-review
of solid content category 1-d shapes are divided
into: cylinder and cone 2, column is divided into:
cuboid, square 3, cone cone of the features of
cuboids and cubes relationship between
characteristics of circular cone is slightly solid
surface area and volume 1, size 2, table
...和
eight and rate. (Omitted) 2, commonly used
time units and their relationships. (Slightly)
with a measurement units Zhijian of of poly 1, and
of method 2, and poly method 3, and of method and
poly method of relationship measurement distance
of method 1, and tool measurement 2, and estimates
16,
九九乘法口诀表
“小九九”的由来
《九九
乘法歌诀》，又常称为“小九九”。现在学生学的“小九九”口诀，是从“一一得一”
开始，到“九九八
十一”止，而在古代，却是倒过来，从“九九八十一”起，到“二二得四”
止。因为口诀开头两个字是“
九九”，所以，人们就把它简称为“九九”。大约到13、14
世纪的时候才倒过来像现在这样“一一得
一……九九八十一”。
中国使用“九九口诀”的时间较早。在《荀子》、《管子》、《淮
南子》、《战国策》等书
中就能找到“三九二十七”、“六八四十八”、“四八三十二”、“六六三十六
”等句子。
由此可见，早在“春秋”、“战国”的时候，《九九乘法歌诀》就已经开始流行了。
现在人们一般把那些有心计、会算计、善谋划的人形容为心里有“小九九”。
数学版乘法口诀表
1×1=1
1×2=2 2×2=4
1×3=3
2×3=6 3×3=9
1×4=4 2×4=8 3×4=12 4×4=16
1×5=5 2×5=10 3×5=15 4×5=20 5×5=25
1×6=6
2×6=12 3×6=18 4×6=24 5×6=30 6×6=36
1×7=7
2×7=14 3×7=21 4×7=28 5×7=35 6×7=42 7×7=49
1×8=8 2×8=16 3×8=24 4×8=32 5×8=40 6×8=48
7×8=56 8×8=64
1×9=9 2×9=18 3×9=27 4×9=36
5×9=45 6×9=54 7×9=63 8×9=72 9×9=81
relationship, established equivalent
relationship 14, and subject: application problem
(4)--scores and percentage application problem
review content overview answers scores, and
percentage application problem of key is:
according to meanings n-line solution. Category
fraction multiplication word problem score
Division applications engineering problem problem
XV, a subject: review of the measurement of the
amount of capacity, measurement and units of
measurement of common units of measurement and
their significance in rate 1, currency, length,
area, volume, unit size, volume, w
and subject:
geometry preliminary knowledge (1)--line and angle
review content line, and segment, and Ray, and
vertical, and parallel, and angle angle of
classification (slightly) 17, and subject:
geometry preliminary knowledge (2)--plane
graphi
, (1) determine standard vol
cs
review content triangle, a
ume (unit
nd
edges shaped, and round, and fan axisymmetric
graphics perimeter and are
hen i
a
combination graphics of area subject : Preliminary
knowledge (3)-review of solid content category 1-d
shapes are divided into: cylinder and cone 2,
column is divided into: cuboid, square 3, cone
cone of the features of cuboids and cubes
relationship between characteristics of circular
cone is slightly solid surface area and volume 1,
size 2, table ...和
eight and rate. (Omitted) 2,
commonly used time units and their relationships.
(Slightly) with a measurement units Zhijian of of
poly 1, and of method 2, and poly method 3, and of
method and poly method of relationship measurement
distance of method 1, and tool measurement 2, and
estimates 16,
九九乘法口诀表
《九九乘法歌诀》，又常称为“小九九”。是从“一一得一”开始，到“九九八十一”的乘法口诀
目录
“小九九”的由来
数学版乘法口诀表
“小九九”的由来
现在小学生学的“小九九”口诀，是从“一一得一”开始，到“九九八十一”为
止，而在古代，
却是倒过来，从“九九八十一”起，到“二二得四”止。因为口诀开头两个字是“九九”
，所以，人
们就把它简称为“小九九”。大约到13、14世纪的时候才倒过来像现在这样“一一得一…
…九
九八十一”。
中国使用“九九口诀”的时间较早。在《荀子》、《管子》、《淮南子
》、《战国策》等
书中就能找到“三九二十七”、“六八四十八”、“四八三十二”、“六六三十六”等
句子。由此可见，
早在“春秋”、“战国”的时候，《九九乘法歌诀》就已经开始流行了。
古希腊、古埃及、古印度、古罗马没有进位制，原则上需要无限大的乘法表，因此不可
能有九九表。例如
希腊乘法表必须列出7x8，70x8，700x8，700x8，7000x8……。相形之
下，由于
九九表基于十进位制，7x8=56，70x8=560，700x8=5600，7000x8=56000，
只需
7x8=56一项代表。
古埃及没有乘法表。考古家发现，古埃及人是通累次迭加法来计算乘积的。例如计算
5x13,先将13+13得26，再迭加26+26=52，然后再加上13得65。
巴比伦算术有进位制，比希腊等几个国家有很大的进步。不过巴比伦算术采用60进位
制，原则上一个“
59x59”乘法表需要59*602=1770项；由于“59x59”乘法表太庞大，巴比伦
人从来
不用类似于九九表的“乘法表”。考古学家也从来没有发现类似于九九表的“59x59”乘
法表。不过
，考古学家发现巴比伦人用独特的
1x1=1,2x2=4,3x3=9……7x7=49,……9x9
=81 ……16x16=256 …… 59x59=3481
的“平方
表”。要计算两个数a,b的乘积，巴比伦人则依靠他们最擅长的代数学，
axb=((a+b)x(a+b)-axa-bxb)2。例如
7x9=((7+9)x(
7+9)-7x7-9x9)2=(256-49-81)2=1262=63.
古玛雅人用20
进位制，跟现代世界通用的十进位制最接近。一个19x19乘法表有190
项，比九九表的45项虽然
大三倍多，但比巴比伦方法还是简便得多。可是考古学家至今还
没有发现任何玛雅乘法表。
用乘法表进行乘法运算，并非进位制的必然结果。巴比伦有进位制，但它们并没有发明
或使用九九表式的
乘法表，而是发明用平方表法计算乘积。玛雅人的数学是西半球古文明中
最先进的，用20进位制，但也
没有发明乘法表。可见从进位制到乘法表是一个不少的进步。
relationship, established equivalent
relationship 14, and subject: application problem
(4)--scores and percentage application problem
review content overview answers scores, and
percentage application problem of key is:
according to meanings corresponds ton-line
solution. Category fraction multiplication word
problem score Division applications engineering
problem problem XV, a subject: review of the
measurement of the amount of capacity, measurement
and units of measuremnt of common units of
measurement and their significance in rate 1,
currency, length, area, volume, unit size, volume,
w
and subject: geometry preliminary knowledge
(1)--line and angle review content line, and
segment, and Ray, and vertical, and parallel, and
angle angle of classification (slightly) 17, and
subject: geometry preliminary knowledge (2)--plane
graphi
, (1) determine standard vol
cs
review content triangle, a
ume (unit
nd
edges shaped, and round, and fan axisymmetric
graphics perimeter and are
hen i
a
combination graphics of area subject : Preliminary
knowledge (3)-review of solid content category 1-d
shapes are divided into: cylinder and cone 2,
column is divided into: cuboid, square 3, cone
cone of the features of cuboids and cubes
relationship between characteristics of circular
cone is slightly solid surface area and volume 1,
size 2, table ...和
eight and rate. (Omitted) 2,
commonly used time units and their relationships.
(Slightly) with a measurement units Zhijian of of
poly 1, and of method 2, and poly method 3, and of
method and poly method of relationship measurement
distance of method 1, and tool measurement 2, and
estimates 16,
中国春秋战国时代不但发明了十进位制，还发明九九表。后来东传入
高丽、日本，经过
丝绸之路西传印度、波斯，继而流行全世界。十进位制和九九表是古代中国对世界文化
的一
项重要的贡献。今日世界各国较少使用希腊等国的乘法。
九九表的特点
1、九九表一般只用一到九这9个数字。
2、九九表包含乘法的可交换性，因此只需要八九七十二
，不需要“九八七十二”，9乘9
有81组积，九九表只需要1+2+3+4+5+6+7+8+9 =
45项积。明代珠算也有采用81组积的
九九表。45项的九九表称为小九九，81项的九九表称为大九
九。
3、古代世界最短的乘法表。玛雅乘法表须190项，巴比伦乘法表须1770项，埃及、<
br>希腊、罗马、印度等国的乘法表须无穷多项；九九表只需4581项。
4、朗读时有节奏，便于记忆全表。
5、九九表存在了至少三千多年。从春秋战国时代就用在筹算
中运算，到明代则改良并
用在算盘上。现在，九九表也是小学算术的基本功。
现在人们一般把那些有心计、会算计、善谋划的人形容为心里有“小九九”。
数学版乘法口诀表
1×1=1
1×2=2 2×2=4
1×3=3 2×3=6
3×3=9
1×4=4 2×4=8 3×4=12 4×4=16
1×5=5
2×5=10 3×5=15 4×5=20 5×5=25
1×6=6 2×6=12
3×6=18 4×6=24 5×6=30 6×6=36
1×7=7 2×7=14
3×7=21 4×7=28 5×7=35 6×7=42 7×7=49
1×8=8
2×8=16 3×8=24 4×8=32 5×8=40 6×8=48 7×8=56 8×8=64
1×9=9 2×9=18 3×9=27 4×9=36 5×9=45 6×9=54
7×9=63 8×9=72 9×9=81
c语言代码
#include
void main()
{int a, b,x=9;
for(a=1;a<=x;a++)
{for(b=1;b<=a;b++)
printf(
printf(
}
}
任意口诀c语言代码
#include
kj (int x);
void main()
relationship, established
equivalent relationship 14, and subject:
application problem (4)--scores and percentage
application problem review content overview
answers scores, and percentage application problem
of key is: according to meanings n-line solution.
Category fraction multiplication word problem
score Division applications engineering problem
problem XV, a subject: review of the measurement
of the amount of capacity, measurement and units
of measurement of common units of measurement and
their significance in rate 1, currency, length,
area, volume, unit size, volume, w
and subject:
geometry preliminary knowledge (1)--line and angle
review content line, and segment, and Ray, and
vertical, and parallel, and angle angle of
classification (slightly) 17, and subject:
geometry preliminary knowledge (2)--plane
graphi
, (1) determine standard vol
cs
review content triangle, a
ume (unit
nd
edges shaped, and round, and fan axisymmetric
graphics perimeter and are
hen i
a
combination graphics of area subject : Preliminary
knowledge (3)-review of solid content category 1-d
shapes are divided into: cylinder and cone 2,
column is divided into: cuboid, square 3, cone
cone of the features of cuboids and cubes
relationship between characteristics of circular
cone is slightly solid surface area and volume 1,
size 2, table ...和
eight and rate. (Omitted) 2,
commonly used time units and their relationships.
(Slightly) with a measurement units Zhijian of of
poly 1, and of method 2, and poly method 3, and of
method and poly method of relationship measurement
distance of method 1, and tool measurement 2, and
estimates 16,
{int i;
printf(请输入要得表的数
scanf(
printf(的乘法口诀表n
kj(i);
}
kj(int x)
{int a, b;
for(a=1;a<=x;a++)
{for(b=1;b<=a;b++)
printf(
printf(
}
}
大九九乘法口诀表 （19×19的乘法口诀表）
1乘的乘法有:
1×1=1 1×2=2 1×3=3 1×4=4 1×5=5 1×6=6
1×7=7 1×8=8 1×9=9 1×10=10 1×11=11
1×12=12
1×13=13 1×14=14 1×15=15 1×16=16 1×17=17 1×18=18
1×19=19
2乘的乘法有:
2×2=4 2×3=6 2×4=8
2×5=10 2×6=12 2×7=14 2×8=16 2×9=18 2×10=20 2×11=22
2×12=24 2×13=26 2×14=28 2×15=30 2×16=32
2×17=34 2×18=36 2×19=38
3乘的乘法有:
3×3=9
3×4=12 3×5=15 3×6=18 3×7=21 3×8=24 3×9=27 3×10=30
3×11=33 3×12=36
3×13=39 3×14=42 3×15=45
3×16=48 3×17=51 3×18=54 3×19=57
4乘的乘法有:
4×4=16 4×5=20 4×6=24 4×7=28 4×8=32 4×9=36 4×10=40
4×11=44 4×12=48
4×13=52 4×14=56 4×15=60
4×16=64 4×17=68 4×18=72 4×19=76
5乘的乘法有:
5×5=25 5×6=30 5×7=35 5×8=40 5×9=45 5×10=50 5×11=55
5×12=60 5×13=65
5×14=70 5×15=75 5×16=80
5×17=85 5×18=90 5×19=95
6乘的乘法有:
6×6=36
6×7=42 6×8=48 6×9=54 6×10=60 6×11=66 6×12=72
6×13=78 6×14=84
6×15=90 6×16=96 6×17=102
6×18=108 6×19=114
7乘的乘法有:
7×7=49
7×8=56 7×9=63 7×10=70 7×11=77 7×12=84 7×13=91
7×14=98 7×15=105
7×16=112 7×17=119 7×18=126
7×19=133
8乘的乘法有:
relationship,
established equivalent relationship 14, and
subject: application problem (4)--scores and
percentage application problem review content
overview answers scores, and percentage
application problem of key is: according to
meanings corresponds ton-line solution. Category
fraction multiplication word problem score
Division applications engineering problem problem
XV, a subject: review of the measurement of the
amount of capacity, measurement and units of
measuremnt of common units of measurement and
their significance in rate 1, currency, length,
area, volume, unit size, volume, w
and subject:
geometry preliminary knowledge (1)--line and angle
review content line, and segment, and Ray, and
vertical, and parallel, and angle angle of
classification (slightly) 17, and subject:
geometry preliminary knowledge (2)--plane
graphi
, (1) determine standard vol
cs
review content triangle, a
ume (unit
nd
edges shaped, and round, and fan axisymmetric
graphics perimeter and are
hen i
a
combination graphics of area subject : Preliminary
knowledge (3)-review of solid content category 1-d
shapes are divided into: cylinder and cone 2,
column is divided into: cuboid, square 3, cone
cone of the features of cuboids and cubes
relationship between characteristics of circular
cone is slightly solid surface area and volume 1,
size 2, table ...和
eight and rate. (Omitted) 2,
commonly used time units and their relationships.
(Slightly) with a measurement units Zhijian of of
poly 1, and of method 2, and poly method 3, and of
method and poly method of relationship measurement
distance of method 1, and tool measurement 2, and
estimates 16,
8×8=64 8×9=72 8×10=80 8×11=88
8×12=96 8×13=104 8×14=112 8×15=120
8×16=128
8×17=136 8×18=144 8×19=152
9乘的乘法有:
9×9=81 9×10=90 9×11=99 9×12=108 9×13=117 9×14=126
9×15=135 9×16=144
9×17=153 9×18=162 9×19=171
10乘的乘法有:
10×10=100 10×11=110 10×12=120
10×13=130 10×14=140 10×15=150 10×16=160
10×17=170 10×18=180 10×19=190
11乘的乘法有:
11×11=121 11×12=132 11×13=143 11×14=154
11×15=165 11×16=176 11×17=187
11×18=198
11×19=209
12乘的乘法有:
12×12=144 12×13=156
12×14=168 12×15=180 12×16=192 12×17=204 12×18=216
12×19=228
13乘的乘法有:
13×13=169
13×14=182 13×15=195 13×16=208 13×17=221 13×18=234
13×19=247
14乘的乘法有:
14×14=196 14×15=210
14×16=224 14×17=238 14×18=252 14×19=266
15乘的乘法有:
15×15=225 15×16=240 15×17=255
15×18=270 15×19=285
16乘的乘法有:
16×16=256
16×17=272 16×18=288 16×19=304
17乘的乘法有:
17×17=289 17×18=306 17×19=323
18乘的乘法有:
18×18=324 18×19=342
19乘的乘法有:
19×19=361
relationship, established equivalent
relationship 14, and subject: application problem
(4)--scores and percentage application problem
review content overview answers scores, and
percentage application problem of key is:
according to meanings n-line solution. Category
fraction multiplication word problem score
Division applications engineering problem problem
XV, a subject: review of the measurement of the
amount of capacity, measurement and units of
measurement of common units of measurement and
their significance in rate 1, currency, length,
area, volume, unit size, volume, w
and subject:
geometry preliminary knowledge (1)--line and angle
review content line, and segment, and Ray, and
vertical, and parallel, and angle angle of
classification (slightly) 17, and subject:
geometry preliminary knowledge (2)--plane
graphi
, (1) determine standard vol
cs
review content triangle, a
ume (unit
nd
edges shaped, and round, and fan axisymmetric
graphics perimeter and are
hen i
a
combination graphics of area subject : Preliminary
knowledge (3)-review of solid content category 1-d
shapes are divided into: cylinder and cone 2,
column is divided into: cuboid, square 3, cone
cone of the features of cuboids and cubes
relationship between characteristics of circular
cone is slightly solid surface area and volume 1,
size 2, table ...和
eight and rate. (Omitted) 2,
commonly used time units and their relationships.
(Slightly) with a measurement units Zhijian of of
poly 1, and of method 2, and poly method 3, and of
method and poly method of relationship measurement
distance of method 1, and tool measurement 2, and
estimates 16,