火树琪花-德玛西亚杯比赛直播

relationship, establi
dge (2)--plane gra
shed equivalent relationship 14, and subject: application problem (4)--scores and percentage application problem review content overview answers scores, and percentage application problem of key is: according to meaning, (1) determine standard volume (units rate corresponds toonship, Then in-line solution. Category fraction multi
p betw
plication word problem score Division applications engineering problem problem XV, a subject: review
preliminary knowlephics review content triangle, and edges shaped, and round, and fan axisymmetric graphics perimeter and area combination graphics of area subject : Preliminary knowledge (3)-review of solid content category 1-d shapes are divided into: cylinder and cone 2, column is divided into: cuboid, square 3, cone cone of the features of cuboids and cubes relationshieen characteristics of circular cone is slightly solid surface area and volume 1, size 2, table ...和
of the measurement of the amount of capacity, measurement and units of measurement of common units of measurement and their significance in rate 1, currency, length, area, volume, unit size, volume, weight and rate. (Omitted) 2, commonly used time units and their relationships. (Slightly) with a measurement units Zhijian of of poly 1, and of method 2, and poly method 3, and of method and poly method of relationship measurement distance of method 1, and tool measurement 2, and estimates 16, and subject: geometry preliminary knowledge (1)--line and angle review content line, and segment, and Ray, and vertical, and parallel, and angle angle of classification (slightly) 17, and subject: geometry
加法速算技巧
1、 不进位的加法算式：（一定要先看清楚进不进位）
加法速算技巧 A ：两位数加一位数：先写上十位数，再接着写上个位数的
和。 例题练习 12+5=17 83+6=89 73+5=78 54+5=59 B 两位数加两位数：先写
十位数的和，再写个位数的和 例题练习 56+23=79 35+62=97 41+28=69
32+54=86 C 多位数加多位数：从高位起，依次写上相同位上的数的和 例题
练习 325+651=976 5237+3562=8799
2、 进位加法算式（一定要观察是否进位） 加法速算技巧 进位加法的关键是向
高一位进1，进1既然已经 是一定的事情，可不可以先进1呢？观察好后可
以从高位先算起。
A 两位数加一位数：先写上十位数加1的和，再接着写个位数的和的个位
数（用二十以内加法口诀） 例题练习 17+8=25 56+7=63 B 两位数加一位数：
先写上两位数凑成整十后的十位数 ，再写上一位数分出一个数后剩余的数。
（即把一位数分开，帮两 位数凑十） 加法速算技巧 15+8= 过程：15+5=20
先写2，8分出5后剩余3，再接着写3。 上面是举的例子，一 分钟速算是
比较实用的教材，通过学习，现在孩子都爱上了数学，数学成绩也提高了不
少，建议 您也给孩子买一套。孩子的信心得到培养了，自己有兴趣是最大的
关键，父母也不用那么整天督促他们了 。
减法速算技巧
1、 不退位的减法算式（很简单，张口即可得结果） 减法速算技巧 两位数减一
位数：先写上十位数，再接着写上个位数的差。 15-2=13 68-3=65 两位数减
两位数：先写上十位数的差，再接着写上个位数的差。 83-21=62 67-32=35 多
位数减多位数：从高位起，依次写上各相 同数位上的数的

relationship, establi
dge (2)--plane gra
shed equivalent relationship 14, and subject: application problem (4)--scores and percentage application problem review content overview answers scores, and percentage application problem of key is: according to meaning, (1) determine standard volume (units rate corresponds toonship, Then in-line solution. Category fraction multi
p betw
plication wproblem score Division applications engineering problem problem XV, a subject: review
preliminary knowlephics review content triangle, and edges shaped, and round, and fan axisymmetric graphics perimeter and area combination graphics of area subject : Preliminary knowledge (3)-review of solid content category 1-d shapes are divided into: cylinder and cone 2, column is divided into: cuboid, square 3, cone cone of the features of cuboids and cubes relationshieen
ord
characteristics of circular cone is slightly solid surface area and volume 1, size 2, table ...和
of the measurement of the amount of capacity, measurement and units of measurement of common units of measurement and their significance in rate 1, currency, length, area, volume, unit size, volume, weight and rate. (Omitted) 2, commonly used time units and their relationships. (Slightly) with a measurement units Zhijian of of poly 1, and of method 2, and poly method 3, and of method and poly method of relationship measurement distance of method 1, and tool measurement 2, and estimates 16, and subject: geometry preliminary knowledge (1)--line and angle review content line, and segment, and Ray, and vertical, and parallel, and angle angle of classification (slightly) 17, and subject: geometry
差。 856-235=621 6798-3672=3162
2、退位的减法算式 减法速算技巧 两位数减一位数 ：先用被减数（两位数）减
去与它的个位数相同的数，再用整十数减去减数（一位数）少减去部分的数。 （把
减数分开两部分） 62-9= 过程：先用62-2=60，60-7=53即可
32-6= 61-3= 73-4= 91-6= 86-8= 两位数减一位数：先用整十数减一位数，
再用这个差加上两位数的个位数。 减法速算技巧 86-8= 过程：先用80-8=72，再
用72+6=78即可。 95-8= 76-9= 83-7= 61-5= 52-6= 两位数减一位数：
先把两个数同时加上一位数的补数（能使一位数凑成整十的数），再做减
法。 81-3= 过程：先把两数同时加上7。再用88-10=78即可。
32-5= 51-3= 65-8= 72-6= 93-5= 两位数减一位数：先把两个数同时减去与
个位数同样多的数。再继续做减法。（把减数分成两部分） 67-9= 过程：先两数
同时减7，再用60-2=58即可。 25-9= 32-7= 53-7= 75-6= 82-5= 两位数
减一位数：用整十数减去一位数与个位数的差。 减法速算技巧 72-6= 过程：6-2=4，
70-4=66即可。 81-6= 75-8= 26-9= 62-7= 55-8= 21-8= 两位数减两位数：
先减去与被减数个位数相 同部分的数（即个位是被减数的个位，十位是减数的十位），
再减去少减去部分的数。（把减数分成两部 分） 95-28= 过程：先用95-25=70。再
用70-3=67即可。 96-59= 83-65= 55-26= 75-57= 81-18= 62-26= 两位数减
两位数：先把两个数同时加上能使减数凑成整十的数，再用减法。 96-58= 过程：
两数同时加上2，再用98-60=38即可。
96-69= 81-57= 75-38= 63-36= 62-27= 41-14= 两位数减两位数：先把两个
数同时减去与被减数的个位数同样多的数，再做减法。（把减数分成两部分） 83-56= 过程：先把两数同时减去3，再用80-53=27即可。
95-68= 77-39= 56-27= 61-32= 63-38= 两位数减两位数：先写上比十位数的差

relationship, establi
dge (2)--plane gra
shed equivalent relationship 14, and subject: application problem (4)--scores and percentage application problem review content overview answers scores, and percentage application problem of key is: according to meaning, (1) determine standard volume (units rate corresponds toonship, Then in- line solution. Category fraction multi
p betw
plication wproblem score Division applications engineering problem problem XV, a subject: review
preliminary knowlephics review content triangle, and edges shaped, and round, and fan axisymmetric graphics perimeter and area combination graphics of area subject : Preliminary knowledge (3)-review of solid content category 1-d shapes are divided into: cylinder and cone 2, column is divided into: cuboid, square 3, cone cone of the features of cuboids and cubes relationshieen
ord
characteristics of circular cone is slightly solid surface area and volume 1, size 2, table ...和
of the measurement of the amount of capacity, measurement and units of measurement of common units of measurement and their significance in rate 1, currency, length, area, volume, unit size, volume, weight and rate. (Omitted) 2, commonly used time units and their relationships. (Slightly) with a measurement units Zhijian of of poly 1, and of method 2, and poly method 3, and of method and poly method of relationship measurement distance of method 1, and tool measurement 2, and estimates 16, and subject: geometry preliminary knowledge (1)--line and angle review content line, and segment, and Ray, and vertical, and parallel, and angle angle of classification (slightly) 17, and subject: geometry
少1的数，个位用20以内的加减法口诀。 减法速算技巧 57-39= 过程：5-3=2先
直接写1，8+9=17再接着写8即可。
85-58= 92-67= 73-46= 81-53= 56-39= 76-38= 两位数减两位数：先用整十数
减去减数，再用这个差加上被减数的个位数。 83-26= 过程：先用80-26=54，再
用54+3=57即可。 85-67= 96-69= 73-38= 82-56= 36-19= 两位数减两位数：
用整十数的差减去个位数的差。 减法速算技巧 72-36= 过程： 70-30=40，6-2=4，
40-4=36 85-67= 51-28= 72-35= 35-16= 73-55= 92-29= 多位数减多位数： 先
把多位数适当分成两部分，灵活运用两位数减一位数和两位数减两位数的心算方法，
直接写出 得数。 减法速算技巧 356-127= 过程：35-12=23，先写22（因要退位），
个 位用20以内的加减法口诀。16-7=9，356-127=229。 6281-3665= 过程： 62-36=26
先直接写26，81-65=16，再接着写16。
9636-6358= 965-326= 8287-5369= 636-258= 7363-2185=
562-136= 7281-3366= 356-189= 6537-2389= 281-123= 多位数减多位数（连续
退位）：从高位起，先写上 比不退位部分数的差少1的数。再接着写被减数部分加
上减数部分的补数的和。 825-567=258 过程： 8-5=3先直接写2，因67的补数是
33，25+33=58， 5736-2879=2857 过程：5-2=3先直接写2，736+121=857即可。
8367-5678= 6515-2837= 5213=3525= 1632-556=
926-629= 863-186= 715-536= 562-365= 631-258= 位的减法算式（很简单，张口
即可得结果） 两位数减一位数：先写上十位数，再接着写上个位数的
差。 15-2=13 68-3=65 两位数减两位数：先写上十位数的差，再接着写上个
位数的差。 83-21=62 67-32=35 多位数减多位数：从高位起，依次写上各相
同数位上的数的差。 856-235=621 6798-3672=3162 2 退位的减法算式 两
位数减一位数：先用被减数（两 位数）减去与它的个位数相同的数，再用整十数减

relationship, establi
dge (2)--plane gra
shed equivalent relationship 14, and subject: application problem (4)--scores and percentage application problem review content overview answers scores, and percentage application problem of key is: according to meaning, (1) determine standard volume (units rate corresponds toonship, Then in- line solution. Category fraction multi
p betw
plication wproblem score Division applications engineering problem problem XV, a subject: review
preliminary knowlephics review content triangle, and edges shaped, and round, and fan axisymmetric graphics perimeter and area combination graphics of area subject : Preliminary knowledge (3)-review of solid content category 1-d shapes are divided into: cylinder and cone 2, column is divided into: cuboid, square 3, cone cone of the features of cuboids and cubes relationshieen
ord
characteristics of circular cone is slightly solid surface area and volume 1, size 2, table ...和
of the measurement of the amount of capacity, measurement and units of measurement of common units of measurement and their significance in rate 1, currency, length, area, volume, unit size, volume, weight and rate. (Omitted) 2, commonly used time units and their relationships. (Slightly) with a measurement units Zhijian of of poly 1, and of method 2, and poly method 3, and of method and poly method of relationship measurement distance of method 1, and tool measurement 2, and estimates 16, and subject: geometry preliminary knowledge (1)--line and angle review content line, and segment, and Ray, and vertical, and parallel, and angle angle of classification (slightly) 17, and subject: geometry
去减数（一位数）少减去部分的数。（把减数分开两部分） 62-9= 过程：先用62-2=60，
60-7=53即可 32-6= 61-3= 73-4= 91-6= 86-8= 两位数减一位数：先用
整十数减一位数，再用这个差加上两位数的个位数。 减法速算技巧 86-8= 过程：
先用80-8=72，再用72+6=78即可。 95-8= 76-9= 83-7= 61-5= 52-6= 两
位数减一位数：先把两个数同时加上一位数的补数（能使一位数凑成整十的数），
再做减法。 81-3= 过程：先把两数同时加上7。再用88-10=78即可。
32-5= 51-3= 65-8= 72-6= 93-5= 两位数减一位数：先把两个数同时减去与
个位数同样多的数。再继续做减法。（把减数分成两部分） 67-9= 过程：先两数
同时减7，再用60-2=58即可。 25-9= 32-7= 53-7= 75-6= 82-5= 两位数
减一位数：用整十数减去一位数与个位数的差。 72-6= 过程：6-2=4， 70-4=66
即可。 81-6= 75-8= 26-9= 62-7= 55-8= 21-8= 两位数减两位数：先减去与
被减数个位数相同部分的数（即个位是 被减数的个位，十位是减数的十位），再减
去少减去部分的数。（把减数分成两部分） 95-28= 过程：先用95-25=70。再用
70-3=67即可。 96-59= 83-65= 55-26= 75-57= 81-18= 62-26= 两位数减两位
数：先把两个数同时加上能使减数凑成整十的数，再用减法。 96-58= 过程：两
数同时加上2，再用98-60=38即可。
96-69= 81-57= 75-38= 63-36= 62-27= 41-14= 两位数减两位数：先 把两个
数同时减去与被减数的个位数同样多的数，再做减法。（把减数分成两部
分） 83-56= 过程：先把两数同时减去3，再用80-53=27即可。
95-68= 77-39= 56-27= 61-32= 63-38= 两位数减两位数：先写上比十位数的差
少1的数，个位用20以内的加减法口诀。 57-39= 过程：5-3=2先直接写1，8+9=17
再接着写8即可。 85-58= 92-67= 73-46= 81-53= 56-39= 76-38= 两位数减
两位数：先用整十数减去减数，再用这个差加上被减数的个位数。 83-26= 过程：

relationship, establi
dge (2)--plane gra
shed equivalent relationship 14, and subject: application problem (4)--scores and percentage application problem review content overview answers scores, and percentage application problem of key is: according to meaning, (1) determine standard volume (units rate corresponds toonship, Then in-line solution. Category fraction multi
p betw
plication wproblem score Division applications engineering problem problem XV, a subject: review
preliminary knowlephics review content triangle, and edges shaped, and round, and fan axisymmetric graphics perimeter and area combination graphics of area subject : Preliminary knowledge (3)-review of solid content category 1-d shapes are divided into: cylinder and cone 2, column is divided into: cuboid, square 3, cone cone of the features of cuboids and cubes relationshieen
ord
characteristics of circular cone is slightly solid surface area and volume 1, size 2, table ...和
of the measurement of the amount of capacity, measurement and units of measurement of common units of measurement and their significance in rate 1, currency, length, area, volume, unit size, volume, weight and rate. (Omitted) 2, commonly used time units and their relationships. (Slightly) with a measurement units Zhijian of of poly 1, and of method 2, and poly method 3, and of method and poly method of relationship measurement distance of method 1, and tool measurement 2, and estimates 16, and subject: geometry preliminary knowledge (1)--line and angle review content line, and segment, and Ray, and vertical, and parallel, and angle angle of classification (slightly) 17, and subject: geometry
先用80-26=54，再用54+3=57即可。 85-67= 96-69= 73-38= 82-56= 36-19= 两
位数减两位数：用整十数的差减去个位数的差。 72-36= 过程： 70-30=40，6-2=4，
40-4=36 85-67= 51-28= 72-35= 35-16= 73-55= 92-29= 多位数减多位数： 先
把多位数适当分成两部分，灵活运用两位数减一位数和两位数减两位数的心算方法，
直接写出 得数。 356-127= 过程：35-12=23，先写22（因要退位），个位用20以
内的 加减法口诀。16-7=9，356-127=229。 6281-3665= 过程： 62-36=26先直接写
26，81-65=16，再接着写16。
9636-6358= 965-326= 8287-5369= 636-258= 7363-2185=
562-136= 7281-3366= 356-189= 6537-2389= 281-123= 多位数减多位数（连续
退位）：从高位起，先写上 比不退位部分数的差少1的数。再接着写被减数部分加
上减数部分的补数的和。 825-567=258 过程： 8-5=3先直接写2，因67的补数是
33，25+33=58， 5736-2879=2857 过程：5-2=3先直接写2，736+121=857即可。
8367-5678= 6515-2837= 5213=3525= 1632-556=
926-629= 863-186= 715-536= 562-365= 631-258=